Fw: Lightbulb stumper...

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Was that 2^(2^n) or 2^(n^2) switching functions of n inputs?  Hmm...
I don't remember!  Oh well, if it is 2^(n^2), [which I think is the
real case], then there are 2^(3^2) = 2^9 = 512 which makes the real
answer not 16 million, but 512^3 = 134,217,728 possible combinations,
which is 8 times worse!

-- 
--------  "And there came a writing to him from Elijah"  [2Ch 21:12]  --------
Robert Jay Brown III rj@eli.elilabs.com  http://www.elilabs.com 1 847 705-0424
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